f(x) = x3 - 2x2 + 3x - 4 f(0) = -4
d axn = naxn-1
dx
a0 = -4
f'(x) = 3x2 - 4x + 3 f'(0) = 3 a1 = 3/1! = 3
f"(x) = 6x - 4 f"(0) = -4 a2 = -4/2! = -2
f'''(x) = 6 f'''(0) = 6 a3 = 6/3! = 1
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If you have a suggestion or a question, please write Oleksandr Kaleniuk, Ph. D., Senior lecturer at DTE / IATE / ISKPI.